A current of 3.6 A flows through an automobile headlight. How many coulombs of charge flow through the headlight in `3.0 h`?

Explanation

To find the total charge (Q) that flows through the automobile headlight, we can use the formula:

\[ Q = I \times t \]

where:
- \( Q \) is the charge in coulombs,
- \( I \) is the current in amperes,
- \( t \) is the time in seconds.

### Step-by-Step Solution:

1. **Identify the given values:**
- Current \( I = 3.6 \, \text{A} \)
- Time \( t = 3.0 \, \text{h} \)

2. **Convert time from hours to seconds:**
- Since \( 1 \, \text{h} = 3600 \, \text{s} \),
- Therefore, \( 3.0 \, \text{h} = 3.0 \times 3600 \, \text{s} = 10800 \, \text{s} \).

3. **Substitute the values into the formula:**
\[ Q = I \times t = 3.6 \, \text{A} \times 10800 \, \text{s} \]

4. **Calculate the charge:**
\[ Q = 3.6 \times 10800 \]
- First, calculate \( 3.6 \times 10800 \):
\[ Q = 38880 \, \text{C} \]

5. **Final Answer:**
- The total charge that flows through the headlight in 3 hours is \( 38880 \, \text{C} \).