Home
Class 12
PHYSICS
In the curcuit shown in figure R1=R2=R3=...

In the curcuit shown in figure `R_1=R_2=R_3=10Omega`. Find the currents through `R_1` and `R_2`

Text Solution

Verified by Experts

The correct Answer is:
A

`V_(R_1)=0`
`:. i_(R_1)=0`
`V_(R_2)=V_(R_3)=10V`
`:. I_(R_2)=i_(R_3)=10/10=1A`
Promotional Banner

Topper's Solved these Questions

  • CURRENT ELECTRICITY

    DC PANDEY ENGLISH|Exercise Exercise 23.7|1 Videos
  • CURRENT ELECTRICITY

    DC PANDEY ENGLISH|Exercise Exercise 23.8|3 Videos
  • CURRENT ELECTRICITY

    DC PANDEY ENGLISH|Exercise Exercise 23.5|2 Videos
  • COMMUNICATION SYSTEM

    DC PANDEY ENGLISH|Exercise Subjective|11 Videos
  • ELECTROMAGNETIC INDUCTION

    DC PANDEY ENGLISH|Exercise Medical entrances gallery|25 Videos