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The wire of potentiometer has resistance...

The wire of potentiometer has resistance `4Omega` and length `1m`. It is connected to a cell of emf 2 volt and internal resistance `1Omega`. If a cell of emf 1.2 volt is balanced by it, the balancing length will be

A

`90 cm`

B

`60 cm`

C

`50 cm`

D

`75 cm`

Text Solution

Verified by Experts

The correct Answer is:
D
`V_(AC)=V_(DE)`
`i(R_(AC))=E=1.2`
`:. (2/(4+1))(4/100)xx l)=1.2`
Solving this equations we get
`l=75 cm`
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DC PANDEY ENGLISH-CURRENT ELECTRICITY-Level 1 Objective
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  4. The wire of potentiometer has resistance 4Omega and length 1m. It is c...

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  5. The potential difference between points A and B, in a section of a cir...

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  6. Two indentical batteries, each of emf 2V andinternal resistance r=1Ome...

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  7. For a cell, the terminal potential difference is 2.2 V, when circuit i...

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  10. A galvanometer has a resistance of 3663Omega. A shunt S is connected a...

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  11. The network shown in figure is an arrangement of nine identical resist...

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  12. The equivalent resistance of the hexagonal network as shown figure be...

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  13. A uniform wire of resistance 18 Omega is bent in the form of a circle....

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  14. Each resistor shown in figure is an infinite network of resistance1Ome...

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  15. In the circuit shown in figure the total resistance between points A a...

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  16. In the circuit shown in figure R=55 Omega the equivalent resistance be...

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  17. The resistance of all the wires between any two adjacent dots is R. Th...

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  18. A uniform wire of resistance 4Omega is bent into circle of radius r. ...

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  19. In the network shown in figure, each resistance is R. The equvalent r...

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  20. The equivalent resistance between the points A and B is (R is the resi...

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