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The resistance of a copper wire and an i...

The resistance of a copper wire and an iron at `20^@C` are `4.1 Omega` and `3.9Omega` respectively. Neglecting any thermal expansion, find the temperature at which resistane of both are equal.
`alpha_(Cu)=4.0xx10^-3K^-1` an `alpha_(Fe)=5.0xx10^-3K^-1`

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To find the temperature at which the resistance of copper and iron wires are equal, we will use the formula for the resistance change with temperature: \[ R = R_0 (1 + \alpha \Delta T) \] Where: - \( R \) is the final resistance, - \( R_0 \) is the initial resistance, - \( \alpha \) is the temperature coefficient of resistance, - \( \Delta T \) is the change in temperature from the initial temperature. ### Step 1: Write the resistance equations for both materials. For copper: \[ R_{Cu} = R_{0,Cu} (1 + \alpha_{Cu} \Delta T) \] \[ R_{Cu} = 4.1 \, \Omega (1 + 4.0 \times 10^{-3} \Delta T) \] For iron: \[ R_{Fe} = R_{0,Fe} (1 + \alpha_{Fe} \Delta T) \] \[ R_{Fe} = 3.9 \, \Omega (1 + 5.0 \times 10^{-3} \Delta T) \] ### Step 2: Set the equations equal to each other. Since we want the resistances to be equal: \[ 4.1 (1 + 4.0 \times 10^{-3} \Delta T) = 3.9 (1 + 5.0 \times 10^{-3} \Delta T) \] ### Step 3: Expand both sides. Expanding both sides gives: \[ 4.1 + 4.1 \times 4.0 \times 10^{-3} \Delta T = 3.9 + 3.9 \times 5.0 \times 10^{-3} \Delta T \] ### Step 4: Calculate the coefficients. Calculating the coefficients: - For copper: \( 4.1 \times 4.0 \times 10^{-3} = 0.0164 \) - For iron: \( 3.9 \times 5.0 \times 10^{-3} = 0.0195 \) So the equation becomes: \[ 4.1 + 0.0164 \Delta T = 3.9 + 0.0195 \Delta T \] ### Step 5: Rearrange the equation. Rearranging gives: \[ 0.0164 \Delta T - 0.0195 \Delta T = 3.9 - 4.1 \] \[ -0.0031 \Delta T = -0.2 \] ### Step 6: Solve for \( \Delta T \). Dividing both sides by -0.0031: \[ \Delta T = \frac{0.2}{0.0031} \approx 64.52 \, \text{°C} \] ### Step 7: Find the final temperature. Adding the initial temperature (20 °C) to the change in temperature: \[ T = 20 + 64.52 \approx 84.52 \, \text{°C} \] ### Final Answer: The temperature at which the resistance of both copper and iron wires are equal is approximately **84.52 °C**.

To find the temperature at which the resistance of copper and iron wires are equal, we will use the formula for the resistance change with temperature: \[ R = R_0 (1 + \alpha \Delta T) \] Where: - \( R \) is the final resistance, - \( R_0 \) is the initial resistance, - \( \alpha \) is the temperature coefficient of resistance, ...
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