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A storage battery with emf 2.6 V loaded ...

A storage battery with emf `2.6 V` loaded with external resistance produces a current `1 A`. In this case, the potential difference between the terminals of the storage battery equals `2 V`. Find the thermal power generated in the battery and the net power supplied by the battery for external circuit.

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To solve the problem, we will follow these steps: ### Step 1: Understand the given values - EMF of the battery, \( E = 2.6 \, \text{V} \) - Current flowing through the circuit, \( I = 1 \, \text{A} \) - Terminal voltage (potential difference across the battery), \( V = 2 \, \text{V} \) ### Step 2: Use the formula for terminal voltage The terminal voltage \( V \) can be expressed in terms of EMF \( E \) and the internal resistance \( R \) of the battery: \[ V = E - I \cdot r \] Where \( r \) is the internal resistance of the battery. ### Step 3: Substitute the known values into the equation Substituting the known values into the equation: \[ 2 = 2.6 - 1 \cdot r \] ### Step 4: Solve for internal resistance \( r \) Rearranging the equation: \[ 1 \cdot r = 2.6 - 2 \] \[ r = 0.6 \, \Omega \] ### Step 5: Calculate the thermal power generated in the battery The thermal power \( P_{\text{thermal}} \) generated in the battery due to its internal resistance can be calculated using the formula: \[ P_{\text{thermal}} = I^2 \cdot r \] Substituting the values: \[ P_{\text{thermal}} = 1^2 \cdot 0.6 = 0.6 \, \text{W} \] ### Step 6: Calculate the net power supplied by the battery to the external circuit The total power supplied by the battery can be calculated using: \[ P_{\text{total}} = E \cdot I \] Substituting the values: \[ P_{\text{total}} = 2.6 \cdot 1 = 2.6 \, \text{W} \] ### Step 7: Calculate the net power supplied to the external circuit The net power \( P_{\text{net}} \) supplied to the external circuit is given by: \[ P_{\text{net}} = P_{\text{total}} - P_{\text{thermal}} \] Substituting the values: \[ P_{\text{net}} = 2.6 - 0.6 = 2 \, \text{W} \] ### Final Answers - Thermal power generated in the battery: \( 0.6 \, \text{W} \) - Net power supplied by the battery for the external circuit: \( 2 \, \text{W} \) ---

To solve the problem, we will follow these steps: ### Step 1: Understand the given values - EMF of the battery, \( E = 2.6 \, \text{V} \) - Current flowing through the circuit, \( I = 1 \, \text{A} \) - Terminal voltage (potential difference across the battery), \( V = 2 \, \text{V} \) ### Step 2: Use the formula for terminal voltage ...
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