In the circuit shown in figure `E_1=7V,E_2=1 V,R_1=2Omega, R_2=2Omega` and `R_3=3Omega` respectively. Find the power supplied by the two batteries.

Answer

A, D

Explanation

Loop equatin in loop 1
`+7-2i_1-3(i_1-i_2)=0`……i
Loop equation in loop 2
`-1+3(i_1-i_2)2i_2=0`………….ii
Solving eqn i and ii we get
`i_1=2A and i_2=1A`
Power supplied by `E_1=E_1i_1=14W`
But power consumed by `E_2=E_2i_2`=1W`