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In the circuit shown in figure , V must ...

In the circuit shown in figure , `V` must be

A

`50V`

B

`80V`

C

`100V`

D

`1290V`

Text Solution

Verified by Experts

The correct Answer is:
B
`100 Omega, 25 Omega` and `20 Omega` are in parallel.
Their net resistance is `10 Omega`
`:. R_("net")=4Omega+10Omega+6Omega=20 Omega`
Hence the main current
`i=E/R_("net")=1A`
Current through either of the resistance
`is i/3 or 1/3 A`
`:.V=iR=(1/3)(9)=3V`
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