Figure shows three resistor configuratio...

Figure shows three resistor configurations `R_1,R_2 and R_3` connected to 3V battery. If the power dissipated by the configuration `R_1,R_2 and R_3` is `P_1, P_2 and P_3`, respectively. Then -

`1:1:1`

`4:4:1`

`4:1:1`

`1:4:4`

Text Solution

Verified by Experts

The correct Answer is:

`R_2=R_3` as `P=V^2/R` and in parallel `V` is same.

Hence, `P_(R_2)=P_(R_3)`
`if R_2=R_3`
Now current through `R_1` is double so `R_1` should be `1/4` th of `R_2` or `R_3` for same power. As `P=i^2R`

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