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Three ammeters A,B, and C of resistances...

Three ammeters `A,B`, and `C` of resistances `R_A,R_b` and `R_C` respectively are joined as shown. When some potential difference is appllied across the terminals `T_1` and `T_2` their readings are `I_A,I_B and I_C` respectively Then,

A

`I_A=I_B`

B

`I_AR_A+I_BR_B=I_CR_C`

C

`I_A/I_C=R_C/R_A`

D

`I_B/I_C=R_C/(R_A+R_B)`

Text Solution

Verified by Experts

The correct Answer is:
A, B, D
a. In series, current is same.
`:. I_A=I_B`
b. `V_A+V_B=V_C`
`:. I_R_A+I_BR_B=I_CR_C`
d. In parallel, current distributes in inverse ratio of resistance
`:. I_B/I_C=I_A/I_C= (R_(C))/(R_A+R_B)`
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