Find the potential difference `V_(AB)` between `A(2m, 1m, 0)` and `B(0, 2m, 4m)` in an electric field,
`E=(xhati-2yhatj+zhatk)V/m`

Explanation

To find the potential difference \( V_{AB} \) between points \( A(2m, 1m, 0) \) and \( B(0, 2m, 4m) \) in the given electric field \( \mathbf{E} = (x \hat{i} - 2y \hat{j} + z \hat{k}) \, \text{V/m} \), we can follow these steps:

### Step 1: Understand the formula for potential difference
The potential difference \( V_{AB} \) between two points A and B in an electric field is given by:
\[ V_{AB} = V_B - V_A = -\int_A^B \mathbf{E} \cdot d\mathbf{s} \]
where \( d\mathbf{s} \) is the differential displacement vector along the path from A to B.
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