A point charge `q_1 = -1.0 muC` is held stationary at the origin. A second point charge `q_2 = + 2.0 muC` moves from the point `(1.0 m, 0, 0)` to `(2.0 m, 0, 0)`. How much work is done by the electric force on `q_2`?

Explanation

To find the work done by the electric force on the charge \( q_2 \) as it moves from the point \( (1.0 \, \text{m}, 0, 0) \) to \( (2.0 \, \text{m}, 0, 0) \), we can follow these steps:

### Step 1: Identify the charges and their positions
- \( q_1 = -1.0 \, \mu\text{C} = -1.0 \times 10^{-6} \, \text{C} \) is located at the origin \( (0, 0, 0) \).
- \( q_2 = +2.0 \, \mu\text{C} = +2.0 \times 10^{-6} \, \text{C} \) moves from \( (1.0 \, \text{m}, 0, 0) \) to \( (2.0 \, \text{m}, 0, 0) \).

### Step 2: Calculate the initial and final distances
- The initial distance \( r_i \) between \( q_1 \) and \( q_2 \) when \( q_2 \) is at \( (1.0 \, \text{m}, 0, 0) \):
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