Home
Class 12
PHYSICS
Assertion: If we see along the axis of a...

Assertion: If we see along the axis of a chaged ring, the magnitudeof electric field is minimum at centre and magnitude of electridc potential is maximum.
Reason: Electric field is a vector quantity while electric potential is scalar.

A

If both Assertion and Reason are true but Reason is the correct explanation of Assertion.

B

If both Assertion and Reason are true but Reason is not the correct explanation of Assertion.

C

If Assertion is true, but the Reason is false.

D

If Assertion is false but the Reason is true.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given question, we need to analyze both the assertion and the reason provided. ### Step-by-Step Solution: 1. **Understanding the Assertion**: The assertion states that when observing along the axis of a charged ring, the electric field is minimum at the center, while the electric potential is maximum at that point. 2. **Electric Potential Calculation**: The electric potential \( V \) at a point along the axis of a charged ring can be expressed as: \[ V_P = \frac{1}{4 \pi \epsilon_0} \frac{Q}{\sqrt{r^2 + x^2}} \] where \( Q \) is the total charge on the ring, \( r \) is the radius of the ring, and \( x \) is the distance from the center of the ring along the axis. 3. **Finding Maximum Potential**: At the center of the ring, when \( x = 0 \): \[ V_P = \frac{1}{4 \pi \epsilon_0} \frac{Q}{r} \] This shows that the potential is maximum at the center of the ring since moving away from the center (increasing \( x \)) will increase the denominator and thus decrease \( V_P \). 4. **Electric Field Calculation**: The electric field \( E \) at the center of the charged ring can be analyzed by considering the contributions from each infinitesimal charge element on the ring. Due to symmetry, the horizontal components of the electric field from opposite charges will cancel out. 5. **Finding Minimum Electric Field**: At the center of the ring, the net electric field \( E \) is: \[ E = 0 \] This indicates that the electric field is indeed minimum (zero) at the center of the ring. 6. **Conclusion on Assertion**: Since the electric field is minimum (zero) at the center and the electric potential is maximum at that point, the assertion is correct. 7. **Understanding the Reason**: The reason states that the electric field is a vector quantity while the electric potential is a scalar quantity. This is a true statement. 8. **Evaluating the Reason as Explanation**: However, while the reason is correct, it does not directly explain why the electric field is minimum and the potential is maximum at the center of the ring. The cancellation of electric field vectors due to symmetry is the key point, which is not addressed by the reason. 9. **Final Evaluation**: Therefore, both the assertion and reason are correct, but the reason does not correctly explain the assertion. ### Final Answer: The correct option is that the assertion is true, the reason is true, but the reason is not the correct explanation of the assertion. ---

To solve the given question, we need to analyze both the assertion and the reason provided. ### Step-by-Step Solution: 1. **Understanding the Assertion**: The assertion states that when observing along the axis of a charged ring, the electric field is minimum at the center, while the electric potential is maximum at that point. 2. **Electric Potential Calculation**: ...
Promotional Banner

Topper's Solved these Questions

  • ELECTROSTATICS

    DC PANDEY ENGLISH|Exercise Level 1 Objective|82 Videos
  • ELECTROSTATICS

    DC PANDEY ENGLISH|Exercise Level 1 Subjective|15 Videos
  • ELECTROSTATICS

    DC PANDEY ENGLISH|Exercise Exercise 24.7|2 Videos
  • ELECTROSTATIC POTENTIAL AND CAPACITORS

    DC PANDEY ENGLISH|Exercise (C) Chapter exercises|50 Videos
  • GRAVITATION

    DC PANDEY ENGLISH|Exercise All Questions|135 Videos

Similar Questions

Explore conceptually related problems

In case of linearly polarised light, the magnitude of the electric field vector

Assertion Due to two charges electric field and electric potential cannot be zero at some point simultaneously. Reason Field is a vector quantity and electric potential is a scalar quantity

At what angle of electric dipole moment with uniform electric field, potential energy is maximum ?

Electric field lines are shown in figure. State whether the electric potential is greater at A or B.

Assertion : Due to two point charges electric field and electric potential can't be zero at some point simultaneously. Reason : Field is a vector quantity and potential a scalar quantity.

Assertion : Electric potential of earth is taken zero. Reason : No electric field exists on earth surface.

Assertion: Electric field is aways directed perpendicular to an equipotential surface. Reason: Equipotential surface is a surface on which at each point potential is same.

Along the axis of a dipole, direction of electric field is always in the direction of electric dipole moment p. Is this statement true of false?

In a certain region of space, the electric field is zero. From this, we can conclude that the electric potential in this region is:

The electric field and the electric potential at a point are E and V respectively.

DC PANDEY ENGLISH-ELECTROSTATICS-Level 1 Assertion And Reason
  1. The electrical potential function for an electrical field directed par...

    Text Solution

    |

  2. The electric potential decreases uniformly from 100 V to 50 V as one m...

    Text Solution

    |

  3. In the uniform electric field shown in figure, find : a. VA-VD b....

    Text Solution

    |

  4. In figure (a), a charge q is placed just outside the centre of a close...

    Text Solution

    |

  5. Net charge within an imaginary cube drawn in a uniform electric field ...

    Text Solution

    |

  6. A hemispherical body of radius R is placed in a uniform electric field...

    Text Solution

    |

  7. A cube has sides of length L = 0.2 m. It is placed with one corner at ...

    Text Solution

    |

  8. Assertion: An independnt negative charge moves itself from point A to ...

    Text Solution

    |

  9. Assertion: When two unlike charges are brought nearer, their electrost...

    Text Solution

    |

  10. Assertion: At a point electric potential is decreasing along x-axis at...

    Text Solution

    |

  11. Assertion: Electric potential on the surface of a charged sphere of ra...

    Text Solution

    |

  12. Assertion: Gauss's theroem can be applied only for a closed surface. ...

    Text Solution

    |

  13. Assertion: In the electric field E=(4hati+4hatj)N//C electric potentia...

    Text Solution

    |

  14. Assertion: Two charges -q each are fixed points A and B. When a third ...

    Text Solution

    |

  15. Assertion: A small electric dipole is moved translatonally from higher...

    Text Solution

    |

  16. Assertion: In case of charged spherical shells, E-r graph is discontin...

    Text Solution

    |

  17. Assertion: If we see along the axis of a chaged ring, the magnitudeof ...

    Text Solution

    |

  18. Units of electric flux are

    Text Solution

    |

  19. A neutral pendulum oscillates in a uniform electric field as shown in ...

    Text Solution

    |