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A charged particle q is shot from a larg...

A charged particle q is shot from a large distance towards another charged particle Q which is fixed, with speed v. It approaches Q up to as closed distance r and then returns. If q were given a speed 2v, the distasnce of approach would be

A

r

B

`2r`

C

`r//2`

D

`r//4`

Text Solution

Verified by Experts

The correct Answer is:
D
`U_i+k_i=U_f+K_f`
`0+1/2mv^2=1/4piepsilon_0.(Qq)/r+or rprop1/v^2`
If v is doubled, the minimum distance r will remain `1/4` the.
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