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Three identical conducting plain paralle...

Three identical conducting plain parallel plates, each of area A are held with equal distance between successive surfaces. Charges`Q`, `2Q`, and `3Q` are placed on them.Neglecting edge effects, find the distribution of charges on the six surfaces.

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To solve the problem of charge distribution on three identical conducting parallel plates with charges \( Q \), \( 2Q \), and \( 3Q \), we will analyze the electrostatic behavior of the system step by step. ### Step-by-Step Solution: 1. **Understanding the Setup:** - We have three parallel plates (let's call them Plate 1, Plate 2, and Plate 3) with equal area \( A \). - The charges on these plates are \( Q \) on Plate 1, \( 2Q \) on Plate 2, and \( 3Q \) on Plate 3. 2. **Identifying Surfaces:** - Each plate has two surfaces. Thus, we have six surfaces in total: - Surface 1 (Plate 1, front) - Surface 2 (Plate 1, back) - Surface 3 (Plate 2, front) - Surface 4 (Plate 2, back) - Surface 5 (Plate 3, front) - Surface 6 (Plate 3, back) 3. **Charge Distribution:** - Since the plates are conductors, charges will redistribute themselves due to electrostatic repulsion until electrostatic equilibrium is reached. 4. **Analyzing the Charges:** - **Plate 1** has a charge of \( Q \). This charge will distribute itself evenly on its surfaces: - Surface 1 (front) will have \( +Q \). - Surface 2 (back) will induce a charge of \( -Q \) on Plate 2's front surface due to electrostatic induction. - **Plate 2** has a charge of \( 2Q \). The back surface (Surface 4) will also have a charge of \( -Q \) from Plate 1's influence: - Surface 3 (front) will have \( +2Q \) (original charge) + \( -Q \) (induced charge) = \( +Q \). - Surface 4 (back) will have \( -Q \). - **Plate 3** has a charge of \( 3Q \). The back surface (Surface 6) will have a charge of \( +3Q \): - Surface 5 (front) will have \( +3Q \) (original charge) + \( -Q \) (induced charge from Plate 2) = \( +2Q \). 5. **Final Charge Distribution:** - Surface 1 (Plate 1, front): \( +Q \) - Surface 2 (Plate 1, back): \( -Q \) - Surface 3 (Plate 2, front): \( +Q \) - Surface 4 (Plate 2, back): \( -Q \) - Surface 5 (Plate 3, front): \( +2Q \) - Surface 6 (Plate 3, back): \( +3Q \) ### Summary of Charge Distribution: - Surface 1: \( +Q \) - Surface 2: \( -Q \) - Surface 3: \( +Q \) - Surface 4: \( -Q \) - Surface 5: \( +2Q \) - Surface 6: \( +3Q \)

To solve the problem of charge distribution on three identical conducting parallel plates with charges \( Q \), \( 2Q \), and \( 3Q \), we will analyze the electrostatic behavior of the system step by step. ### Step-by-Step Solution: 1. **Understanding the Setup:** - We have three parallel plates (let's call them Plate 1, Plate 2, and Plate 3) with equal area \( A \). - The charges on these plates are \( Q \) on Plate 1, \( 2Q \) on Plate 2, and \( 3Q \) on Plate 3. ...
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