Capacitance of a conductor is `1muF`. What charge is required to raise its potential to `100 V`?

Explanation

To find the charge required to raise the potential of a conductor to a certain voltage, we can use the formula that relates capacitance (C), charge (Q), and voltage (V):

\[ Q = C \times V \]

### Step-by-Step Solution:

1. **Identify the given values:**
- Capacitance (C) = 1 microfarad (µF)
- Voltage (V) = 100 volts (V)

2. **Convert capacitance to standard units:**
- 1 microfarad (µF) = \( 1 \times 10^{-6} \) farads (F)
- Therefore, \( C = 1 \times 10^{-6} \, \text{F} \)

3. **Substitute the values into the formula:**
- Using the formula \( Q = C \times V \):
\[ Q = (1 \times 10^{-6} \, \text{F}) \times (100 \, \text{V}) \]

4. **Calculate the charge:**
\[ Q = 1 \times 10^{-6} \times 100 = 1 \times 10^{-4} \, \text{C} \]

5. **Convert the charge to microcoulombs:**
- Since \( 1 \, \text{C} = 10^{6} \, \mu\text{C} \):
\[ Q = 1 \times 10^{-4} \, \text{C} = 100 \, \mu\text{C} \]

### Final Answer:
The charge required to raise the potential of the conductor to 100 V is **100 microcoulombs (µC)**.