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Find the charge stored in the capacitor....

Find the charge stored in the capacitor.

Text Solution

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As we said earlier also, current will flow in loop `ABCDA` when charging is over. And this current is
`i=("Net emf")/("Total resistance")=24/(5+3)=3A`

Now` PD` across the capacitor is equal to the `PD` across the `5Omega` resistance.
Hence `V=V_A-V_B=iR=(3)(5)=15V`
`:. q=CV=(2xx15)muC=30muC`
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