A capacitor has a capacitance of `7.28 muF`. What amount of charge must be placed on each of its plates to make the potential difference between its plates equAl to `25.0 V`?

Explanation

To solve the problem of finding the charge that must be placed on each plate of a capacitor with a capacitance of \(7.28 \, \mu F\) to achieve a potential difference of \(25.0 \, V\), we can use the formula that relates charge (\(Q\)), capacitance (\(C\)), and voltage (\(V\)):

### Step-by-Step Solution

1. **Identify the given values**:
- Capacitance, \(C = 7.28 \, \mu F = 7.28 \times 10^{-6} \, F\)
- Voltage, \(V = 25.0 \, V\)

...