A parallel air capacitance `245muF` has a charge of magnitude `0.48muC` on each plate. The plates are `0.328 mm` apart.
(a) What is the potential difference between the plates?
(b) What is the area of each plate?
(c) What is the surface charge density on each plate?

Explanation

To solve the problem step by step, we will address each part of the question systematically.

### Given Data:
- Capacitance, \( C = 245 \, \mu F = 245 \times 10^{-6} \, F \)
- Charge, \( Q = 0.48 \, \mu C = 0.48 \times 10^{-6} \, C \)
- Distance between plates, \( d = 0.328 \, mm = 0.328 \times 10^{-3} \, m \)

### (a) Finding the Potential Difference Between the Plates
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