A capacitor of capacitance `C` carrying charge `Q` is connected to a source of emf `E`. Finally, the charge on capacitor would be

Options

A. `Q`
B. `Q+CE`
C. `CE`
D. none of these

Explanation

To solve the problem of finding the final charge on a capacitor connected to a source of emf \( E \), we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Capacitor**:
A capacitor is a device that stores electrical energy in an electric field. The charge \( Q \) on a capacitor is related to its capacitance \( C \) and the voltage \( V \) (or emf \( E \)) across it by the formula:
\[ Q = C \cdot V \]

2. **Initial Condition**:
Initially, the capacitor has a charge \( Q \). However, when it is connected to a source of emf \( E \), the voltage across the capacitor will change.

3. **Connecting to the Source**:
When the capacitor is connected to the emf source \( E \), the voltage across the capacitor becomes equal to the emf. Therefore, we can substitute \( E \) for \( V \) in the formula:
\[ Q_{\text{final}} = C \cdot E \]

4. **Final Charge Calculation**:
The final charge on the capacitor after being connected to the emf source will be:
\[ Q_{\text{final}} = C \cdot E \]

5. **Conclusion**:
The final charge on the capacitor will be \( C \cdot E \), regardless of the initial charge \( Q \) it had before being connected to the emf source.

### Final Answer:
The final charge on the capacitor will be \( C \cdot E \).

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