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Two capacitors C1=1muF and C2=3muF each ...

Two capacitors `C_1=1muF` and `C_2=3muF` each are charged to a potential difference of `100V` but with opposite polarity as shown in the figure. When the switch `S` is closed, the new potential difference between the points `a` and `b` is

A

`200V`

B

`100V`

C

`50V`

D

`25V`

Text Solution

Verified by Experts

The correct Answer is:
C
Total charge `=3xx100-1xx100=200muC`
common potential (in parallel) after S is closed is
`V=("total charge")/("Total capacity")`
`=(200muC)/(4muF)`
`=50V`
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