A charged particle projected in a magnetic field
`B=(3hati+4hatj)xx10^-2T`
The acceleration of the particle is found to be
`a=(xhati+2hatj)m/s^2`
find the value of `x`

Explanation

To find the value of \( x \) in the given problem, we will follow these steps:

### Step 1: Understand the relationship between force, acceleration, and magnetic field
The force \( \mathbf{F} \) acting on a charged particle moving in a magnetic field is given by the equation:
\[ \mathbf{F} = q (\mathbf{v} \times \mathbf{B}) \]
where \( q \) is the charge of the particle, \( \mathbf{v} \) is the velocity vector, and \( \mathbf{B} \) is the magnetic field vector.
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