When as proton has a velocity `v=(2hati+3hatj)xx10^6m/s`, it experience a force `F=-(1.28xx10^-13hatk)` When its velocity is along the z-axis, it experience a force along the `x`-axis. What is the magnetic field?

Explanation

To solve the problem, we will follow these steps:

### Step 1: Understand the Given Information
We are given:
- Velocity of the proton: \( \mathbf{v} = (2\hat{i} + 3\hat{j}) \times 10^6 \, \text{m/s} \)
- Force experienced by the proton: \( \mathbf{F} = -1.28 \times 10^{-13} \hat{k} \)

### Step 2: Use the Lorentz Force Equation
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