A magnetic field of `(4.0xx10^-3hatk)T` exerts a force `(4.0hati+3.0hatj)xx10^-10N` on a particle having a charge `10^-9C` and moving in te `x-y` plane. Find the velocity of the particle.
Text Solution
AI Generated Solution
To find the velocity of the particle moving in the magnetic field, we can use the formula for the magnetic force acting on a charged particle:
\[
\mathbf{F} = q (\mathbf{v} \times \mathbf{B})
\]
Where:
- \(\mathbf{F}\) is the magnetic force,
...
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