Two particles `A` and `B` of masses `m_A` and `m_B` respectively and having the same charge are moving ina plane. A uniform magnetic field exists perependicular to this plane. The speeds of the particles are `v_A` and `v_B` respectively and the trajectories are as shown in the figure. Then,
A
`m_Av_Altm_Bv_B`
B
`m_Av_Agtm_Bv_B`
C
`m_Altm_B and v_Altv_B`
D
`m_A=m_B and v_A=v_B`
Text Solution
Verified by Experts
Radius of the circle `=(mv)/(Bq)` `or radius propmv ` if `B` and `q` are same. `(Radius)_Agt(Radius)_B` `m_V V_Agtm_Bv_B` `:.` correct option is `b`
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