A proton a deuteron and an `alpha` - particle having the same kinetic energy are moving in circular trajectories in a constant magnetic of the trajectories of these particle, then
A
`r_(alpha)=r_pltr_d`
B
`r_(alpha)gtr_dgtr_p`
C
`r_(alpha)=r_dgtr_p`
D
`r_p=r_d=r_(alpha)`
Text Solution
Verified by Experts
Radius of the circular path is given by `r=(mv)/(Bq)=sqrt((2Km))/(Bq)` Here `K` is the kinetic energy to the particle, Therefore, `rpropsqrtm/q` if `K` and `B` are same `r_p:r_d=r_(alpha)=sqrt1/1:sqrt2/1:sqrt4/1=1:sqrt2:1` Hence, `r_(alpha)=r_pltr_d` `:.` correct option is a.
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