A horizontal rod `0.2 m` long is mounted on a balnce and carries a current. At the location of the rod a uniform horizontal magnetic field has magnitude `0.067 T` and direction perpendicular to the rod. The magnetic force on the rod is measured by the balance and is found to be `0.13N`. What is the current?

Explanation

To solve the problem, we will use the formula for the magnetic force acting on a current-carrying conductor in a magnetic field. The formula is given by:

\[ F = I \cdot L \cdot B \cdot \sin(\theta) \]

Where:
- \( F \) is the magnetic force (in Newtons),
- \( I \) is the current (in Amperes),
- \( L \) is the length of the rod (in meters),
...