A circular loop of radius `R=20` cm is placed in a uniform magnetic field `B=2T` in `xy`-plane as shown in figure. The loop carries a current `i=1.0 A` in the direction shown in figure. Find the magnitude of torque acting on the loop.
Text Solution
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Magnitude of torque is given by `|tau|=Mbsintheta` `Here , M=NiA=(1)(1.0)(pi)(0.2)^2` `=(0.04pi)(A-m^2`) `B=2T` and `theta= ` angle between `M` and `B =90^@` `:. |tau|=(0.04pi)(2)sin90^@` `=0.25N-m`
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