A current path shaped as shown in figure produces a magnetic field at `P`, the centre of the arc. If the arc subtends an angle of `30^@` and the radius of the arc is `0.6 m`, what are the magnitude and direction of the field produced at P if the current is `3.0 A`.
Text Solution
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The magnetic field at `P` due to the straight segments `AC` and `DE` is zero. `CD` is arc of circle. `:. B=(theta/(2pi))((mu_0i)/(2R))` (N=1) `B= ((mu_0)/(4pi))(i/R)theta` `:. B=(10^-7)(3.0/0.6)(pi/6)` ltbr.gt `=2.62xx10^-7T`
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