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In the magnetic meridian of a certain pl...

In the magnetic meridian of a certain place, the horizontal component of earth's magnetic fied is `0.26 G` and the dip angle is `60^@`. Find
a. Vertical component of earth's magnetic field
b. the net magnetic field at this place

Text Solution

Verified by Experts

Given, `H=0.26G` and `theta=60^@`
a. `tantheta=V/H`
`:. V=Htantheta=(0.26)tan60^@`
` =0.45G`
`b.H=B_ecostheta`
`B_e=H/(costheta)=0.26/(cos60^@)`
`=0.52G`
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