Home
Class 12
PHYSICS
A magnet suspended at 30^@ with magnetic...

A magnet suspended at `30^@` with magnetic meridian makes an angle of `45^@` with the horizontal. What shall be the actual value of the angle of dip?

Text Solution

AI Generated Solution

To solve the problem, we need to find the actual value of the angle of dip (φ) when a magnet is suspended at an angle of 30° with the magnetic meridian and makes an angle of 45° with the horizontal. ### Step-by-Step Solution: 1. **Understanding the Setup**: - The magnet is suspended at an angle of 30° with respect to the magnetic meridian. - It makes an angle of 45° with the horizontal. ...
Promotional Banner

Topper's Solved these Questions

  • MAGNETICS

    DC PANDEY ENGLISH|Exercise INTRODUCTORY EXERCISE|1 Videos
  • MAGNETICS

    DC PANDEY ENGLISH|Exercise SUBJECTIVE_TYPE|1 Videos
  • MAGNETIC FIELD AND FORCES

    DC PANDEY ENGLISH|Exercise Medical entrance s gallery|59 Videos
  • MAGNETISM AND MATTER

    DC PANDEY ENGLISH|Exercise Medical gallery|1 Videos

Similar Questions

Explore conceptually related problems

A magnetic needle suspended in a vertical plane at 30^@ from the magnetic meridian makes an angle of 45^@ with the horizontal. Find the true angle of dip.

At magnetic poles of earth, angle of dip is

The real angle of dip, if a magnet is suspended at an angle of 30^(@) to the magnetic meridian and the dip needle makes an angle of 45^(@) with horizontal, is:

The real angle of dip, if a magnet is suspended at an angle of 30^(@) to the magnetic meridian and the dip needle makes an angle of 45^(@) with horizontal, is:

A dip circle lying initially in the magnetic meridian is rotated through angle theta in the horizontal plane. The ratio of tangent of apparent angle of dip to true angle of dip is

A magnetic needle free to rotate in a fixed vertical plane stays in a direction making an angle of 60^@ with the horizontal. If the dip at that plane is 37^@ , find the angle of the fixed vertical plane with the meridian.

If a magnet is suspended an angle 30^(@) to the magnetic field at any point on eath. Near the north pole.

At 45^@ to the magnetic meridian, the apparent dip is 30^@ . Find the true dip.

A magnetic needle is free to rotate in a vertical plance which makes an angle of 60^@ with the magnetic meridian. If the needle stays in a direction making an angle of tan^(-1) (2sqrt(3)) with the horizontal, what would be the dip at that place?

The time of vibration of a dip needle in the vertical plane is 3 sec the magnetic needle is made to vibrate in the horizontal plane, the time of vibration is 3sqrt2 s . Then angle of dip will be-