A cyclotron's oscillator frequency is `10MHz`. What should be the operating magnetic field fro accelerating protons? If the radius of its dees is `60cm`, what is the kinetic energy (in `MeV`) of the proton beam produced by the acceleration? `(e-1.60xx10^-19C,m_p=1.67xx10^-27kg, 1MeV=1.6xx10^-13J)`
Text Solution
AI Generated Solution
To solve the problem step by step, we need to find the operating magnetic field for the cyclotron and then calculate the kinetic energy of the proton beam produced by the acceleration.
### Step 1: Convert the oscillator frequency to standard units
The given oscillator frequency is \(10 \text{ MHz}\).
\[
f = 10 \times 10^6 \text{ Hz} = 10^7 \text{ Hz}
\]
...
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