What is the value of `B` that can be set up at the equator to permit a proton of speed `10^7m//s` to circulate around the earth? `[R=6.4xx10^6m,m_p=1.67xx10^-27kg]`
Text Solution
AI Generated Solution
To find the value of the magnetic field \( B \) that allows a proton to circulate around the Earth at the equator with a speed of \( 10^7 \, \text{m/s} \), we can use the concept of centripetal force and the magnetic force acting on the proton.
### Step-by-Step Solution:
1. **Identify the Forces**:
The magnetic force acting on the proton must provide the necessary centripetal force to keep it moving in a circular path. The magnetic force \( F_B \) is given by:
\[
F_B = q v B
...
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