In the Bohr model of the hydrogen atom, the electron circuulates around the nucleus in a path of radius `5xx10^-11m` at a frequency of `6.8xx10^15Hz`.
a. What value of magnetic field is set up at the centre of the orbit?
b. What is the equivalent magnetic dipole moment?

Explanation

To solve the problem step by step, we will address both parts of the question: calculating the magnetic field at the center of the orbit and finding the equivalent magnetic dipole moment.

### Part (a): Calculate the Magnetic Field at the Center of the Orbit

1. **Identify the given values:**
- Radius of the orbit, \( r = 5 \times 10^{-11} \, \text{m} \)
- Frequency of the electron, \( f = 6.8 \times 10^{15} \, \text{Hz} \)
- Charge of the electron, \( Q = 1.6 \times 10^{-19} \, \text{C} \)
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