A charge `q=4muC` has as instantaneous velociyt `v=(2hati-3hatj+hatk)xx10^6m/s` in a uniform magnetic field `B=(2hati+5hatj-3hatk)xx10^-2T`. What is the force on the charge?

Explanation

To find the magnetic force on a charge moving in a magnetic field, we can use the formula:

\[ \vec{F} = q (\vec{v} \times \vec{B}) \]

where:
- \( \vec{F} \) is the magnetic force,
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