A deuteron (the nucleus of an isotope of hydrogen) has a mass of `3.34 xx 10^-27` kg and a charge of `+e`. The deuteron travels in a circular path with a radius of `6.96 mm` in a magnetic field with magnitude `2.50 T`.
(a) Find the speed of the deuteron.
(b) Find the time required for it to make half of a revolution.
(c) Through what potential difference would the deuteron have to be accelerated to acquire this speed?

Answer

B

Explanation

a. `r=(mv)/(Bq)impliesv=(Bqr)/m`
b. `t=T/2=(pim)/(Bq)`
c. `r=sqrt((2qVm))/(Bq)`
`:. V=(r^2B^2q^2)/(2qm) =(r^2B^2q)/(2m)`