A particle of mass `m` and charge `q` is projected into a region having a perpendicular magnetic, field `B`. Find the angle of deviation of the particle as it comes out of the magnetic field if the, width of the region is `b`, which is very slightly less than `(mv)/(2Bq)`

Explanation

To solve the problem, we will follow these steps:

### Step 1: Understand the motion of the charged particle in a magnetic field
When a charged particle moves through a magnetic field, it experiences a magnetic force that acts perpendicular to both the velocity of the particle and the magnetic field. This results in circular motion.

### Step 2: Determine the radius of the circular path
The radius \( r \) of the circular path of a charged particle in a magnetic field is given by the formula:
\[
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