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A particle of mass m and charge q moves ...

A particle of mass m and charge q moves with a constant velocity v along the positive `x-` direction. It enters a region containing a uniform magnetic field B directed along the negative z direction, extending from `x=a` to `x=b`. The minimum value of v required so that the particle can just enter the region `xgtb` is

A

`(qBb)/m`

B

`(qBa)/m`

C

`(qB(b-a))/m`

D

`(qB(b+a))/(2m)`

Text Solution

Verified by Experts

The correct Answer is:
C
`(b-a)=` radius of circular part
`=(mv)/(Bq)`
`:. V=(Bq(b-a))/m`
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