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A uniformly charged ring of radius R is ...

A uniformly charged ring of radius `R` is rotated about its axis with constant linear speed `v` of each of its particle. The ratio of electric field to magnetic field at a point `P` on the axis of the ring distant `x=R` from centre of ring is `( c` is speed of light )

A

`c^2/v`

B

`v^2/c`

C

`v/c`

D

`c/v`

Text Solution

Verified by Experts

The correct Answer is:
A

`E=1/(4piepsilon_0)(qx)/((R^2+x^2)^(3/2))`
`B=(mu_0iR^2)/(2(R^2+x^2)^(3/2))`
where, `i=qf=q(V/(2piR))`
`c=1/(sqrt((epsilon_0mu_0)`
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