Home
Class 12
PHYSICS
The current through an inductor of 1H is...

The current through an inductor of `1H` is given by `i =3t sin t`. Find the voltage across the inductor.

Text Solution

AI Generated Solution

To find the voltage across the inductor, we will use the formula for the voltage across an inductor, which is given by: \[ V_L = L \frac{di}{dt} \] where: - \( V_L \) is the voltage across the inductor, - \( L \) is the inductance (in henries), - \( \frac{di}{dt} \) is the rate of change of current with respect to time. ...
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC INDUCTION

    DC PANDEY ENGLISH|Exercise Exercise 27.4|3 Videos

  • ELECTROMAGNETIC INDUCTION

    DC PANDEY ENGLISH|Exercise Exercise 27.5|3 Videos

  • ELECTROMAGNETIC INDUCTION

    DC PANDEY ENGLISH|Exercise Exercise 27.2|4 Videos

  • CURRENT ELECTRICITY

    DC PANDEY ENGLISH|Exercise Medical entrances gallery|97 Videos

  • ELECTROMAGNETIC WAVES

    DC PANDEY ENGLISH|Exercise Sec C|22 Videos

Similar Questions

Explore conceptually related problems

The current through an inductor of 1H is given by i =3tsin t . Find the voltage across the inductor.

If the current through an inductor of 2 H is given by I = t sin t A , then the voltage across the inductor is

The current through inductor of 2H is given by I=2t cos 2t . The voltage across the inductor is

The current in an LCR circuit is given by I=20sin (100pi t+(pi)/(6))A . The voltage across the the inductance L of 0.1 H at t = 0 will be

A capacitor of capacitance Chas initial charge Q_0 and connected to an inductor L as shown. At t=0 switch S is closed. The current through the inductor when energy in the capacitor is three times the energy of inductor is

The current through an inductor of impedance 10Omega lags behind the voltage by a phase of 60^(@) when just the inductor is connected to the ac source. Now the inductor is connected to a 5Omega resistance in series, then the net impedance of the circuit is

A 100 Omega resistasnce is connected in series with a 4 H inductor. The voltage across the resistor is V_R=(2.0V)sin(10^3 rad//s)t : (a) Find the expession of circuit current (b) Find the inductive reactance (c) derive an expression for the voltage across the inductor,

A 100 Omega resistasnce is connected in series with a 4 H inductor. The voltage across the resistor is V_R=(2.0V)sin(10^3 rad//s)t : (a) Find the expession of circuit current (b) Find the inductive reactance (c) derive an expression for the voltage across the inductor,

The current in ampere through an inductor is i=(20t+10) Here t is in second. The induced emf in the inductor 4V. Total flux linked with the inductor at t= 2 is a

The current in ampere through an inductor is i=(10+20t) Here t is in second. The induced emf in the inductor 4V. The self inductance of the indicator is, L…..H,