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In the figure shown as uniform magnetic ...

In the figure shown as uniform magnetic field `|B|=0.5T` is perpendicular to the plane of circuit. The sliding rod of length `l=0.25 m` moves uniformly with constant speed `v=4ms^-1`. If the resistance of the sllides is `2Omega`, then the current flowing through the sliding rod is

A

`0.1A`

B

`0.17A`

C

`0.08`

D

`0.03A`

Text Solution

Verified by Experts

The correct Answer is:
A
`e=Bvl=0.5xx4xx0.25=0.5V`
`12Omega` and `4Omega` are parallel.Hence, their net resistance `R=3Omega`
`i=e/(R+r)=0.5/(32)=0.1A`
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