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A 50 Hz AC source of 20 V is connected a...

A `50 Hz AC` source of `20 V` is connected across `R ` and `C` as shown in figure.
The voltage across `R` is `12 V`. The voltage across `C` is

A

`8V`

B

`16V`

C

`10V`

D

not possible to determine unless value of `R` and `C` are given

Text Solution

Verified by Experts

The correct Answer is:
B
`V_C=sqrt(V^2-V_R^2)=sqrt((20)^2-(12)^2)`
`= 16V`.
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