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In the circuit shown in figureure the AC...

In the circuit shown in figureure the `AC` source gives a voltage `V=20cos(2000t)`. Neglecting source resistance, the voltmeter and and ammeter readings will be
.

A

`0V,2.0A`

B

`0V,1.4A`

C

`5.6V,1.4A`

D

`8V,2.0A`

Text Solution

Verified by Experts

The correct Answer is:
C
`X_L=omegaL=(5 xx10^(-3))(2000)=10 Omega`
`X_C=1/(omegaC)=1/((2000)50xx10^(-6))=10Omega`
Since, `X_L=X_C` circuit is in resonance.
`Z=R=(6+4)=10Omega`
`I_("rms")=V_("rms")/Z=((20//sqrt2))/10=1.414A`
This is also the reading of ammeter.
`V=4I_("rms")`
`~~5.6` Volt.
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