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In a series C-R circuit shown in figureu...

In a series `C-R` circuit shown in figureure, the applied voltage is `10 V` and the voltage across capacitor is found to`8 V`. The voltage across `R`, and the phase difference between current and the applied voltage will respectively be
.

A

`6V, tan^-1(4/3)`

B

`3V,tan^-1(3/4)`

C

`6V,tan^-1(3/4)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
`V_R=sqrt(V^2-V_C^2)=sqrt((10)^2-(8)^2)=6V`
`tanphi=X_C/X_R=V_C/V_R=8/6=4/3`
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