In the figure shown, the reading of voltmeters are `V_1 = 40 V, V_2 = 40 V` and `V_3 = 1 0 V`. Find

(a) the peak value of current
(b) the peak value of emf
(c) the value of `L` and `C`.

Answer

A, B, C, D

Explanation

(a) `i_("rms")=V_1/R=40/4=10A`
`i_0=sqrt2i_("rms")=10sqrt2A`
(b) `E_0/sqrt2=sqrt(V_1^2+(V_2-V_1)^2)=50V`
(c) `X_L=(omegaL)=V_2/i_("rms")=40/10=4Omega`
`:. L=4/omega=4/(100pi)H=1/(25pi)H`
`X_C=1(omegaC)=V_1/i_("rms")=10/10=1Omega`
`:. C=1/omega=1/(100pi)F`.