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About 5% of the power of a 100 W light b...

About `5%` of the power of a `100 W` light bulb is converted to visible radiation. What is the average intensity of visible radiation
(a) at a distance of `1 m` from the bulb?
(b) at a distance of `10 m` ?
Assume that the radiation is esmitted isotropically and neglect reflection.

Text Solution

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To solve the problem, we need to calculate the average intensity of visible radiation emitted by a light bulb at two different distances. ### Given Data: - Power of the light bulb, \( P = 100 \, \text{W} \) - Percentage of power converted to visible radiation = \( 5\% \) - Distance \( r_1 = 1 \, \text{m} \) - Distance \( r_2 = 10 \, \text{m} \) ...
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