The sunlight reaching the earth has maximum electric field of 810V `(m^-1)`. What is the maximum magnetic field in this light?

Explanation

To find the maximum magnetic field in sunlight given the maximum electric field, we can use the relationship between the electric field (E) and the magnetic field (B) in electromagnetic waves. The formula that relates these two fields is:

\[ B = \frac{E}{c} \]

Where:
- \( B \) is the maximum magnetic field,
- \( E \) is the maximum electric field,
- \( c \) is the speed of light in a vacuum, approximately \( 3 \times 10^8 \, \text{m/s} \).

### Step-by-Step Solution:

1. **Identify the given values:**
- Maximum electric field, \( E = 810 \, \text{V/m} \)
- Speed of light, \( c = 3 \times 10^8 \, \text{m/s} \)

2. **Substitute the values into the formula:**
\[ B = \frac{E}{c} = \frac{810 \, \text{V/m}}{3 \times 10^8 \, \text{m/s}} \]

3. **Calculate the maximum magnetic field:**
\[ B = \frac{810}{3 \times 10^8} = 2.7 \times 10^{-6} \, \text{T} \]

4. **Convert the magnetic field into microtesla:**
\[ B = 2.7 \, \mu\text{T} \]

### Final Answer:
The maximum magnetic field in the sunlight reaching the Earth is \( 2.7 \, \mu\text{T} \).

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