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Suppose that the electric field amplitud...

Suppose that the electric field amplitude of an electromagnetic wave us `E_0=120 N// C` and that its frequency is `50.0 MHz`.
(a) Determine` B_0,omega,k` and `lambda`,
(b) find expressions for `E` and `B`.

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To solve the given problem step by step, we will determine the magnetic field amplitude \( B_0 \), angular frequency \( \omega \), wave number \( k \), wavelength \( \lambda \), and then find the expressions for the electric field \( E \) and magnetic field \( B \). ### Step-by-Step Solution: **Given:** - Electric field amplitude \( E_0 = 120 \, \text{N/C} \) - Frequency \( f = 50.0 \, \text{MHz} = 50.0 \times 10^6 \, \text{Hz} \) ### Part (a): Determine \( B_0, \omega, k, \lambda \) 1. **Calculate \( B_0 \)**: The relationship between the electric field amplitude \( E_0 \) and the magnetic field amplitude \( B_0 \) in an electromagnetic wave is given by: \[ B_0 = \frac{E_0}{c} \] where \( c \) is the speed of light (\( c \approx 3 \times 10^8 \, \text{m/s} \)). \[ B_0 = \frac{120 \, \text{N/C}}{3 \times 10^8 \, \text{m/s}} = 4 \times 10^{-7} \, \text{T} \] 2. **Calculate \( \omega \)**: The angular frequency \( \omega \) is related to the frequency \( f \) by: \[ \omega = 2\pi f \] Substituting the value of \( f \): \[ \omega = 2\pi \times 50.0 \times 10^6 \approx 314159.27 \, \text{rad/s} \] 3. **Calculate \( k \)**: The wave number \( k \) is given by: \[ k = \frac{\omega}{c} \] Substituting the values of \( \omega \) and \( c \): \[ k = \frac{314159.27}{3 \times 10^8} \approx 1.047 \times 10^{-3} \, \text{m}^{-1} \] 4. **Calculate \( \lambda \)**: The wavelength \( \lambda \) can be calculated using the relationship: \[ \lambda = \frac{c}{f} \] Substituting the values: \[ \lambda = \frac{3 \times 10^8}{50.0 \times 10^6} = 6 \, \text{m} \] ### Summary of Part (a): - \( B_0 = 4 \times 10^{-7} \, \text{T} \) - \( \omega \approx 314159.27 \, \text{rad/s} \) - \( k \approx 1.047 \times 10^{-3} \, \text{m}^{-1} \) - \( \lambda = 6 \, \text{m} \) ### Part (b): Find expressions for \( E \) and \( B \) 1. **Expression for \( E \)**: The general expression for the electric field in an electromagnetic wave is: \[ E(x, t) = E_0 \sin(\omega t - kx) \] Substituting the known values: \[ E(x, t) = 120 \sin(314159.27 t - 1.047 x) \] 2. **Expression for \( B \)**: The general expression for the magnetic field is: \[ B(x, t) = B_0 \sin(\omega t - kx) \] Substituting the known values: \[ B(x, t) = 4 \times 10^{-7} \sin(314159.27 t - 1.047 x) \] ### Final Expressions: - \( E(x, t) = 120 \sin(314159.27 t - 1.047 x) \) - \( B(x, t) = 4 \times 10^{-7} \sin(314159.27 t - 1.047 x) \)

To solve the given problem step by step, we will determine the magnetic field amplitude \( B_0 \), angular frequency \( \omega \), wave number \( k \), wavelength \( \lambda \), and then find the expressions for the electric field \( E \) and magnetic field \( B \). ### Step-by-Step Solution: **Given:** - Electric field amplitude \( E_0 = 120 \, \text{N/C} \) - Frequency \( f = 50.0 \, \text{MHz} = 50.0 \times 10^6 \, \text{Hz} \) ...
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