A pole of height 4 m is kept in front of a vertical plane mirror
of length 2m. The lower end of the mirror is at a height of 6m form the grown
.the horizontal distance betweem the mirror and the pole is 2m. Upto what
minimum and maximum heights a man can see the image of top of the pole at a
horizontal distance of 4m (from the mirror O standing on the same horizontal
line which is passing through the pole and the horizontal point below the
mirror?

Explanation

`PQ="Pole", MN="Image of pole" `
`(HG)/(GN)=(BD)/(BN)`
`:. BD=((HG)(BN))/(GN)=((2)(6))/(2)`
`=6 M`
Minimum height required `=AD=BD+AB=10m`
Further ,`(IG)/(GN)=(BE)/(BN)`
`:. BE=((IG)(BN))/(GN)=((4)(6))/(2)=12 m`
`:.` Maximum height required `=AE`
`=BE+AB=16 m`.