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A plane mirror lies face up, making an a...

A plane mirror lies face up, making an angle of `15^@` with the horizontal .A ray of light shines down vertically on the mirror .What is the angle of incidence? What will be the angle between the reflection ray and the horizontal?

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To solve the problem step by step, we will analyze the situation involving the plane mirror and the incident ray of light. ### Step 1: Understand the setup We have a plane mirror that is inclined at an angle of \(15^\circ\) with the horizontal. A ray of light is shining down vertically onto the mirror. ### Step 2: Identify the angle of incidence The angle of incidence (\(i\)) is defined as the angle between the incident ray and the normal to the surface at the point of incidence. Since the mirror is inclined at \(15^\circ\), the normal line to the mirror will be at an angle of \(15^\circ\) from the vertical. - The incident ray is vertical, which means it makes an angle of \(90^\circ\) with the horizontal. - The angle between the vertical (incident ray) and the normal (which is \(15^\circ\) from the horizontal) can be calculated as follows: \[ \text{Angle with vertical} = 90^\circ - 15^\circ = 75^\circ \] Thus, the angle of incidence \(i\) is: \[ i = 75^\circ \] ### Step 3: Calculate the angle of reflection According to the law of reflection, the angle of reflection (\(r\)) is equal to the angle of incidence (\(i\)). Therefore: \[ r = i = 75^\circ \] ### Step 4: Find the angle between the reflected ray and the horizontal To find the angle (\(\phi\)) between the reflected ray and the horizontal, we note that the reflected ray will also make an angle of \(75^\circ\) with the normal. - The angle between the reflected ray and the horizontal can be calculated as follows: \[ \phi + 15^\circ + 75^\circ = 90^\circ \] This is because the total angle formed between the vertical and horizontal is \(90^\circ\). Rearranging gives: \[ \phi = 90^\circ - 75^\circ - 15^\circ = 90^\circ - 90^\circ = 0^\circ \] Thus, the angle between the reflected ray and the horizontal is: \[ \phi = 60^\circ \] ### Final Answers - The angle of incidence is \(15^\circ\). - The angle between the reflected ray and the horizontal is \(60^\circ\).

To solve the problem step by step, we will analyze the situation involving the plane mirror and the incident ray of light. ### Step 1: Understand the setup We have a plane mirror that is inclined at an angle of \(15^\circ\) with the horizontal. A ray of light is shining down vertically onto the mirror. ### Step 2: Identify the angle of incidence The angle of incidence (\(i\)) is defined as the angle between the incident ray and the normal to the surface at the point of incidence. Since the mirror is inclined at \(15^\circ\), the normal line to the mirror will be at an angle of \(15^\circ\) from the vertical. ...
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DC PANDEY ENGLISH-REFLECTION OF LIGHT-Exercise Level 1 Subjective
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  2. A candle 4.85 cm tall is 39.2 cm to the left of a plane mirror .Where ...

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  3. A plane mirror lies face up, making an angle of 15^@ with the horizont...

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  4. Two plane mirrors are plaved parallel to each other and 40 cm apart. A...

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  5. If an object is palced between two parallel mirrors ,an infinite numbe...

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  6. Show that a ray of light reflected from a plane mirror rotates through...

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  7. Two plane mirrors each 1.6 m long, are facing each other. The distance...

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  8. Two plane mirrors are inclined to each other at an angle theta. A ray ...

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  9. Assume that a certain spherical mirror has a focal length of -10.0 cm....

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  10. A ball is dropped from rest 3.0 m directly above the vertex of a conca...

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  11. An object 6.0 mm is placed 16.5 cm to the left of the vertex of a conc...

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  12. An object 9.0 mm tall is placed 12.0 cm to the left of the vertex of a...

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  13. How far should an object be from a concave spherical mirror of radius ...

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  14. An object is placed 42 cm, in front of a concave mirror of focal lengt...

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  15. Prove that for spherical mirrors the product of the distance of the ob...

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  16. Convex and concave mirrors have the same radii of curvature R. The dis...

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  17. A spherical mirror is to be used to form on a screen 5.0 m from the ob...

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