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The angle of minimum deviation for a gla...

The angle of minimum deviation for a glass prism with `mu=sqrt3` equals the refracting angle of the prism. What is the angle of the prism?

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To solve the problem, we need to find the angle of the prism (denoted as \( A \)) given that the angle of minimum deviation (\( D \)) is equal to the refracting angle of the prism, and the refractive index (\( \mu \)) of the prism is \( \sqrt{3} \). ### Step-by-Step Solution: 1. **Understanding the Given Information:** - We know that the angle of minimum deviation \( D \) is equal to the angle of the prism \( A \). - The refractive index \( \mu \) of the prism is given as \( \sqrt{3} \). 2. **Using the Formula for Refractive Index:** - The formula relating the refractive index \( \mu \), the angle of the prism \( A \), and the angle of minimum deviation \( D \) is: \[ \mu = \frac{\sin\left(\frac{A + D}{2}\right)}{\sin\left(\frac{A}{2}\right)} \] - Since \( D = A \), we can substitute \( D \) in the formula: \[ \mu = \frac{\sin\left(\frac{A + A}{2}\right)}{\sin\left(\frac{A}{2}\right)} = \frac{\sin(A)}{\sin\left(\frac{A}{2}\right)} \] 3. **Substituting the Value of \( \mu \):** - We substitute \( \mu = \sqrt{3} \): \[ \sqrt{3} = \frac{\sin(A)}{\sin\left(\frac{A}{2}\right)} \] 4. **Using the Trigonometric Identity:** - We can express \( \sin(A) \) using the double angle formula: \[ \sin(A) = 2 \sin\left(\frac{A}{2}\right) \cos\left(\frac{A}{2}\right) \] - Substituting this into our equation gives: \[ \sqrt{3} = \frac{2 \sin\left(\frac{A}{2}\right) \cos\left(\frac{A}{2}\right)}{\sin\left(\frac{A}{2}\right)} \] - The \( \sin\left(\frac{A}{2}\right) \) terms cancel out (assuming \( \sin\left(\frac{A}{2}\right) \neq 0 \)): \[ \sqrt{3} = 2 \cos\left(\frac{A}{2}\right) \] 5. **Solving for \( \cos\left(\frac{A}{2}\right) \):** - Rearranging gives: \[ \cos\left(\frac{A}{2}\right) = \frac{\sqrt{3}}{2} \] - The angle whose cosine is \( \frac{\sqrt{3}}{2} \) is \( 30^\circ \): \[ \frac{A}{2} = 30^\circ \] 6. **Finding the Angle of the Prism \( A \):** - Multiplying both sides by 2: \[ A = 60^\circ \] ### Final Answer: The angle of the prism \( A \) is \( 60^\circ \). ---

To solve the problem, we need to find the angle of the prism (denoted as \( A \)) given that the angle of minimum deviation (\( D \)) is equal to the refracting angle of the prism, and the refractive index (\( \mu \)) of the prism is \( \sqrt{3} \). ### Step-by-Step Solution: 1. **Understanding the Given Information:** - We know that the angle of minimum deviation \( D \) is equal to the angle of the prism \( A \). - The refractive index \( \mu \) of the prism is given as \( \sqrt{3} \). ...
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